The Metal Vapor Of The Fuse Material Under Joule Heating
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When an overload current or short-circuit current flows through drop out fuse, the fuse material will heat up rapidly due to the thermal effect of the current. According to Joule's law, Q=I²RT, the heat generated is proportional to the square of the current; the larger the current, the more heat is generated per unit time.
Once the fuse material reaches its melting point, it begins to melt and break, generating an electric arc at the break point. The temperature of this arc can reach 6000-10000℃. At this extreme temperature, the molten fuse metal rapidly vaporizes, forming a large amount of metal vapor. This metal vapor fills the gap between the fuse and the break point, intensifying the arc and making it burn more intensely.
